How to declare an 3-dimensional array in C#?

Question

I just tried to create an 3-dimensional array in C# (which seems to work, at least there are no errors)

private int[,,] myarray = new int [sizeX,sizeY,sizeZ];

but when I try to write to the array

myarray [valueX,valueY,valueZ] = 1;

I get the following error:

error CS0266: Cannot implicitly convert type `float' to `int'. An explicit conversion exists (are you missing a cast?)

How do I use multidimensional arrays correctly?

Thanks in advance

Greets, xLuboex

Answer 1

Best Answer

Answer by Rostam24 · Sep 26, 2015 at 08:19 PM

sounds like the values you are putting in the array are floats, so you would need to do this: flloat[,,] myarray = new float[sizeX, sizeY, sizeZ];

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xLuboex · Sep 26, 2015 at 08:34 PM 0

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Already tried that, doesn't change anything.

Rostam24 xLuboex · Sep 26, 2015 at 08:43 PM 0

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Any chance valueX, valueY and valueZ are floats?

xLuboex Rostam24 · Sep 26, 2015 at 08:55 PM 0

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They actually are myVector.x, myVector.y and myVector.z. I don't know if Unity treads the values of a vector as floats...

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