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Question by Wolfshadow · Mar 25, 2016 at 12:55 AM · c#randomrandom.range

Semi-Random Or Engine

Hello Everyone, I want to be able to pick a random number within a certain range, and I am aware of random.range();

However, I want to be able to have, say, a 75% chance of 1-20, 15% chance of 21-30, 10% chance of 31-35, if that makes sense. Thank you.

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Answer by Bunny83 · Mar 25, 2016 at 01:12 AM

Pseudo random number generators have a uniform number distribution. You have to do it in two seperate steps. First use a random float value to define your area and then do another Random.Range to get the actual number

 int GetValue()
 {
     float n = Random.value;
     if (n < 0.75f)
         return Random.Range(1, 21);
     n -= 0.75f;
     if (n < 15f)
         return Random.Range(21, 31);
     return Random.Range(31, 36);
 }

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