disable UI button

This leaves the button on the screen with the disabled color and the user can't click it:

 yourButton.interactable = false;

This leaves the button on the screen, the user can't click it, but does NOT use the disabled color:

 yourButton.enabled = false;

This removes the button from the UI entirely:

 yourButton.gameObject.SetActive(false);

You might just want to make it non-interactable (then the button stays, but turn grey by default). You do this from your script by putting this in the script of the object where the button is located:

 GetComponent<Button>().interactable = false;

try this script. is working.

video- disable button

 using System.Collections;
 using System.Collections.Generic;
 using UnityEngine;
 using UnityEngine.UI;
 
 [RequireComponent(typeof(Button))]
 public class disable : MonoBehaviour {
 
     //GUI btn = (GameObject)Instantiate(Resources.Load("MyButton"));
 
     //GameObject btn = GameObject.CreatePrimitive(PrimitiveType.Plane);
     //public Object btn = Object.Instantiate(Resources.Load("MyButton"));
     //public Color newColor;
     //public Button mybutton;
     //public Color newColor;
 
     public Sprite blockA;
     public Sprite blockA_disable;
     public bool condition;
     public Button mybutton;
     public int counter;
 
     void start()
     {
         mybutton = GetComponent<Button> ();
     }
 
     public void changebutton()
     {
         counter++;
         if (counter % 2 == 0) {
             mybutton.image.overrideSprite = blockA;
                  //condition for working button.
         } else {
             mybutton.image.overrideSprite = blockA_disable;
                  //condition for disable button
         }
 
     }
 
 }
 

very easy

 public gameobject yourbutton;
 public void DisableButton ()
 {
       yourbutton.setActive(false);
 }
 
 //you have to put this script function in onclick() of the button component