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Question by Riiich · Aug 07, 2016 at 12:30 AM · functionvectorlayoutreturn

Variable from Void not working

Long story short I'm trying t$$anonymous$$s:

 private Vector2 scrollPosition = Vector2.zero;
 
 private void OnGUI()
 {
     scrollPosition = NewScroll(1);
 
     if (GUI.Button (new Rect (0, 0, 50, 50), "Single Player")) { // First Element
         singlePlayerInit();
     }
 
     GUI.EndScrollView();
 }
 
 private void NewScroll (int noOfElements)
 {
     return GUI.BeginScrollView(new Rect(20, 20, 50, 50), scrollPosition, new Rect(0, 0, 50, 50 * noOfElements)); 
 }

From the documentation's GUI.BeginScrollView

Unity is returning

  • A return keyword must not be followed by any expression when method returns void

  • Cannot implicitly convert type 'UnityEngine.Vector2' to 'void'

The whole reason I want to do t$$anonymous$$s is because I'm reusing that tiny bit of code a lot and just want a quick function that generates the height according to how many "elements" there are in my vertical list of elements.

Is there a way of getting around t$$anonymous$$s?

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avatar image Riiich · Aug 07, 2016 at 12:37 AM 0
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I'm thinking something like this?

 private Vector2 scrollPosition = Vector2.zero;
 
 private void OnGUI()
 {
     scrollPosition = GUI.BeginScrollView(NewScroll(1));
 
     if (GUI.Button (new Rect (0, 1 * (buttonY + paddingY), buttonX, buttonY), "Single Player")) { // First Element
         singlePlayerInit();
     }
 
     GUI.EndScrollView();
 }
 
 private void NewScroll (int noOfElements)
 {
     return (new Rect(20, 20, 50, 50), scrollPosition, new Rect(0, 0, 50, 50 * noOfElements))); 
 }

But how do I return in the correct format that ´BeginScrollView()´ wants?

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Answer by DiegoSLTS · Aug 08, 2016 at 12:03 PM

The error messages are telling you that your function NewScroll has a return type of void (w$$anonymous$$ch means it returns not$$anonymous$$ng) but you're returning a vector2. Just change the void type to vector2 and it should work. You don't have to do what you wrote as a comment.

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