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Question by Tedward61194 · Jun 29, 2011 at 11:03 PM · errorsyntax-errorvoidunexpected-symbolcs1519

Not expecting void Start

Hi, I'm trying to make a very basic melee attack, but when I tried adding a cooldown to the attack, I got the error "...(10.12):error CS1519: Unexpected symbol 'void' in class, struct, or interface member declaration" My problem is that the error is refereeing to the "void Start" in the initialization, w$$anonymous$$ch has to be there, what did I do wrong? Here's the code, thanks a bunch.

 using UnityEngine;
 using System.Collections;
 
 public class PlayerAttack : MonoBehaviour {
     public GameObject target;
     public float attackTimer;
     public float coolDown
 
     // Use t$$anonymous$$s for initialization
     void Start () {
         attackTimer = 0;
         coolDown = 2.0f;
     }
     
     // Update is called once per frame
     void Update () {
         if(attackTimer > 0)
             attackTimer -= Time.fixedDeltaTime;
         
         if(attackTimer < 0)
             attackTimer = 0;
         
         if(Input.GetKeyUp(KeyCode.F)) {
             if(attackTimer ==0){
                 Attack();
                 attackTimer = coolDown;
             }
         }
         
     }
     
     private void Attack() {
         float distance = Vector3.Distance(target.transform.position, transform.position);
         
         Vector3 dir = (target.transform.position - transform.position).normalized;
             
         float direction = Vector3.Dot(dir, transform.forward);
         
         Debug.Log(direction);
         
         if(distance < 2.5f) {
             if(direction > 0) {
             EnemyHealth eh = (EnemyHealth)target.GetComponent("EnemyHealth");
             eh.AddjustCurrentHealth(-10);
             }
         }
     }
 }
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avatar image Bunny83 · Jun 29, 2011 at 11:10 PM 0
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Fixed the code highlighting. Please make sure you highlight your code in the future. Just select the code and press the "101 010" button.

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Answer by Dreamblur · Jun 29, 2011 at 11:04 PM

You forgot to put a semi-colon after the last variable before your Start method.

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avatar image Bunny83 · Jun 29, 2011 at 11:11 PM 0
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Yep :D takes around 2 - 3 sec. to spot that.

avatar image Dreamblur · Jun 29, 2011 at 11:14 PM 0
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I already knew what it was as soon as I read the error -- it's kinda a basic error. =P

avatar image Bunny83 · Jun 29, 2011 at 11:34 PM 0
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Well, it's most of the time a missing semicolon but not always ;)

avatar image Dreamblur · Jun 29, 2011 at 11:47 PM 0
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In my case, it usually is (or a bracket). XD

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Answer by Tedward61194 · Jun 29, 2011 at 11:10 PM

Wow thanks, I really hate programming sometimes X)

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avatar image Bunny83 · Jun 29, 2011 at 11:29 PM 0
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First, don't use answers as comments!

Second, The compiler have to read and translate your code. actually you don't need any new lines in the code, you could write all in one single line (The only exception are single-line-comments of course). Each statement have to be terminated by a semicolon so the compiler knows it's finished. If after coolDown comes a {get;} the compiler would create a property instead of a normal field for example.

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