Move character by X units on the left

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  if (Input.GetKey(KeyCode.D) && tr.position == pos)
         {
             pos += Vector3.right;
         }
         else if (Input.GetKey(KeyCode.A) && tr.position == pos)
         {
             pos += Vector3.left;
         }

Answer 1

Best Answer

Answer by dan_wipf · Sep 11, 2018 at 07:05 PM

instead of vector3.left you can use

new Vector3(1.25f,0,0);

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Schmeep · Sep 11, 2018 at 07:07 PM 0

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you're a lifesaver! thanks a bunch :D

dan_wipf · Sep 12, 2018 at 10:43 AM 0

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you’re welcome :)

Bunny83 · Sep 12, 2018 at 11:32 AM 0

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Or simply

 pos += Vector3.left * 1.25f;

or in this particular case we can do

 pos.x += 1.25f;

Note that the last example doesn't work with transform.position, only when you have a seperate Vector3 variable

Bunny83 · Sep 12, 2018 at 11:35 AM 1

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Also note that you usually want to multiply the value by Time.deltaTime to be framerate independent. This however means you most likely have to use a larger speed value. So usually you would do something like this:

 pos += Vector3.left * speed * Time.deltaTime;

where "speed" is in "units per second".

Move character by X units on the left

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