Looking for nearest increment of 10

Question

Hi I have a piece of code that generates a random receipt value ( eg. 17.60 $). Now I want a piece of code that looks for the nearest increment of 10 based on that receipt value. ( 20$ in my case)

How would I do such a thing? I was thinking about using modulo, but I'm not quite sure how that would look.

thanks in advance.

Answer 1

Best Answer

Answer by Atenrev · Jul 29, 2019 at 05:35 PM

You could think about doing something like this

 if (n > 1000) 
 {
     n = Mathf.RoundInt(n/1000)*1000;
 }
 else if (n > 100) 
 {
     n = Mathf.RoundInt(n/100)*100;
 }
 else if (n > 10) 
 {
     n = Mathf.RoundInt(n/10)*10;
 }
 else if (n > 5)
 {
     n = 10;
 }
 else
 {
     n = 0;
 }

But I don't find it too elegant. If I think of something better, I'll comment it.

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Answer 2

Answer by Gilles_aerts · Jul 29, 2019 at 06:40 PM

I've done something simular and used the mathF.round function. that seemed to have done the trick, thank you.

Incase anyone wants to know what I did:

customerPay = Mathf.RoundToInt((receiptValue / 10)) * 10 ; if (customerPay < receiptValue) { customerPay += 10; }

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Looking for nearest increment of 10

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