Random numbers please help

Question

How can I set a value to an int var by random?

I mean if I have a variable called "numbercount" and I want to give it a value from 1-5 for exapmle, how can I do it?

Answer 1

Best Answer

Answer by landon912 · Nov 12, 2012 at 07:30 PM

 Random.Range(1,5)

returns a random int from ONE to FOUR

DON'T FORGET, with integers it is ONE LESS THAN THE LAST ONE.

Thus, Random.Range(0,10) will give you "ten different" random numbers (that is, 0 through 9 inclusive).

To "roll a dice" it would be Random.Range(1,7).

it's ALWAYS one less than the end number you supply in the brackets. (the reason for this is to do with working with arrays. If you don't understand this yet, don't worry about it. Just don't forget it's one less than the end number.)

Add comment · Show 5 · Share

smirlianos · Nov 12, 2012 at 07:33 PM 0

Share

Thanks!! :)

Random username · Nov 12, 2012 at 07:37 PM 5

Share

Just to clarify, that means numbers 1, 2, 3 and 4 could possibly be returned. 5 will never be.

smirlianos · Nov 12, 2012 at 07:39 PM 0

Share

oh, ok, so for 1-5 I should put Random.Range(1,6)?

Eric5h5 · Nov 12, 2012 at 07:45 PM 0

Share

http://docs.unity3d.com/Documentation/ScriptReference/Random.Range.html

landon912 · Nov 12, 2012 at 09:25 PM 0

Share

Thanks for fixing my answer. Also solves another problem. Thanks

Random numbers please help

1 Reply

Your answer

Welcome to Unity Answers

Follow this Question

Related Questions