Determining if my target is standing upright

Question

What is the best way to determine if my target is standing upright after it has been $$anonymous$$t with a physics force?

I would like to be able to have a threshold value if the target is leaning. If it is leaning say 45 degrees or less, it is still considered upright.

Thanks,

Answer 1

Best Answer

Answer by Jesse Anders · Dec 06, 2010 at 02:51 AM

Don't use Euler angles for t$$anonymous$$s. Instead, check the object's local 'up' vector to see how 'upright' it is. (An easy way to do t$$anonymous$$s would be to compare the local up vector's 'y' value - assuming y is up - to some threshold value, e.g. .7. If you want to express the threshold in terms of an angle, you can compute the threshold for the y value from that angle using trig.)

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BigToe · Dec 06, 2010 at 08:25 AM 0

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Thanks. I completely forgot about the transform.up for some reason. i'll put my code below.

Answer 2

Answer by BigToe · Dec 06, 2010 at 08:26 AM

T$$anonymous$$s is what I ended up using after Jesse reminded me of the transform.up vector.

if (transform.up.y < .6f){
// code here
}

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Answer 3

Answer by BigToe · Dec 06, 2010 at 12:23 AM

Don't know if t$$anonymous$$s is the correct way to do it, but it seems to work.

Basically look at the eular angles. If the angle is greater than 45, then I considered the target knocked down.

if (360 - Mathf.Abs(transform.eulerAngles.x - 360) > 45 || 360 - Mathf.Abs(transform.eulerAngles.z - 360) > 45)
    {
        //The target is knocked over.  Do what you please.
    }

I'm guessing there may be a more elegant way.

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Answer 4

Answer by diegodimap · Aug 23, 2017 at 01:25 PM

nice! it worked for me, I was using eulerAngle, but it do not work properly:

[1]: /storage/temp/100482-standing.png

standing.png (10.3 kB)

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Determining if my target is standing upright

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