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Question by EmJay · Jan 13, 2013 at 07:53 PM · cameralookattranslate

Why my camera rotates around gameobject

So when I try to translate my camera's position by -60,60,-60 plus gameobjects position

(Vec3(-60,60,-60)+(Vec3(gO.x,gO.y,gO.z)))

the camera starts to rotate around the target object so rapidly that the terrain gets redrawn only in few frames and the object (Cube) only starts to get drawn when it has fallen enough.

The scene contain terrain, camera and cube with collision detection working properly. This happens only when I use the translation. The camera is set to look at the Cube.

transform.Translate(Player.transform.position+vec); transform.LookAt(Player.transform.position);

The Cube itself doesn't rotate.

EDIT: I don't know why the Translate won't work but I got it working by just skipping the Translate and just applying the result directly at the camera's position property. Or Translate doesn't apply its result into position property at all.

EDIT2:

 //Reference works so that is not the problem
 public GameObject Player;
 Vector3 vec = new Vector3(-60,60,-90);
 
 void Start () {
         
     }
     
     // Update is called once per frame
     void Update () {
     
     }
     void LateUpdate(){       transform.Translate(Player.transform.position+vec); 
         transform.LookAt(Player.transform.position);
 
     }
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Answer by Lovrenc · Jan 13, 2013 at 07:56 PM

You are moving the camera AND rotating it (lookAt). Therefore gameObject is allways in different location related to camera. This causes your camera to rotate.

 (Vec3(-60,60,-60)+(Vec3(gO.x,gO.y,gO.z))) //this could be done like this
 Vec3(-60,60,-60)+ gO
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avatar image EmJay · Jan 13, 2013 at 08:37 PM 0
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Don't really get what you are saying. If the Cube is at 30,30,30 then the camera is at -30,90,-30 and looking at the Cube's position and when the Cube moves to 0,30,30 camera should be at -60,90,-30 and looking at 0,30,30. So what part in the Translation causes the rotation to happen.

EDIT: Nevermind, I used the Translate to set the position directly ins$$anonymous$$d of calculating it. Dummy me I guess.

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