Hi All,
I have i window in that one question and 4 Toggle buttons. and one next button.
My task is if i click the next button i need to display the second question in the same window.
I wrote code like this:
void DoMyWindow4(int windowID)
{
GUI.Label(new Rect(10,10,500,100),"1) A pendulum length is 20m , find the Timeperiod of the pendulum ?",newfontStyle);
toggleTxt1 = GUI.Toggle(new Rect(30, 50, 150, 40), toggleTxt1, " 8.975s");
toggleTxt2 = GUI.Toggle(new Rect(130, 50, 150, 40), toggleTxt2, " 9.975s");
toggleTxt3 = GUI.Toggle(new Rect(250, 50, 150, 40), toggleTxt3, " 7.975s");
toggleTxt4 = GUI.Toggle(new Rect(350, 50, 150, 40), toggleTxt4, " 6.975s");
if(GUI.Button(new Rect(500,50,50,30), "NEXT"))
{
GUI.Label(new Rect(10,10,500,100),"2) A pendulum time period is 15s , find the Length of the pendulum ?",newfontStyle);
toggleTxt1 = GUI.Toggle(new Rect(30, 50, 150, 40), toggleTxt1, " 10.975cm");
toggleTxt2 = GUI.Toggle(new Rect(130, 50, 150, 40), toggleTxt2, "15.975cm");
toggleTxt3 = GUI.Toggle(new Rect(250, 50, 150, 40), toggleTxt3, " 13.975cm");
toggleTxt4 = GUI.Toggle(new Rect(350, 50, 150, 40), toggleTxt4, " 9.975cm");
}
}
that is my window. But if i click the next button that question didn’t change.
can i get any solution or any help.
Thankyou
Shankar