One of the numbers as Second ?

Question

Hello again, I want to ask a question about random methods. I want to create an object at random seconds.

Such like ;

1st object instantiates wit$$anonymous$$n 3 seconds 2nd object instantiates seconds between 3 & 6 seconds

how can i do that using random method ? sorry for my bad english.

Answer 1

Answer by Jamora · Aug 03, 2013 at 05:37 PM

Yes, you can use either the System.Random class or Unity's own Random class.

To get a random number between any two numbers, say x and y ( x

So to make t$$anonymous$$s concrete:
your first object would get a random number as Random(0f,3f);
your second would be 3f + Random( 0f,(6-3)f );

The "f"s mean floats, in case you only want integers you should leave them out.

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Alp-Giray-Savrum · Aug 03, 2013 at 06:15 PM 0

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I've changed my idea about code. I want to apply this like this code below:

 var randomNumber : int;
 
     
     
     function Update()
     {
         
             
             
                 ChosenOne();
             
     }
     
     
     
     function ChosenOne()
     {
     
         randomNumber = Random.Range(1, 4);
         
         Debug.Log(randomNumber.ToString());
         
         yield WaitForSeconds(3 + randomNumber);
     
     }

how can i apply this as you said ? Could you edit ? thanks a lot :)

Jamora · Aug 03, 2013 at 07:25 PM 0

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My answer explains exactly how to achieve a random number from what ever continuous range you choose. I will try to explain further, but not write your code for you.

You must first know how much of your value is random and how much will always happen. If you want to get a value between 3 and 6; 1, 2 and 3 can be considered as always happening, and the random element is either 0,1,2 or 3. Because the first 3 always happen, you only need to add the random element (0 to 3) to it.

You need to read my answer(s) again and then apply the explained basic principle to your problem.

One of the numbers as Second ?

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