Show variable name from a class as String

So i have this class:

class ActorKnowledge {
	var state : boolean;
	
    function ActorKnowledge (state : boolean) {
        this.state = state;
    }
    
	function ActorKnowledge (state : boolean, selectedList :  List.<ActorKnowledge>) {
        this.state = state;
    	selectedList.Add(this);
    }
    
}

And its used in several Lists. I need to have them display in the editor from reading the Lists that contain them but I can’t convert the class name to string. This is what i have so far:

	for (var playerKnowledge : ActorKnowledge in scriptPlayer.playerKnowledgeList){
		 var knowledgeName = playerKnowledge.ToString();
		 		  
		if (!playerKnowledge.state){
			if ( GUI.Button (Rect (leftPadding, row01PositionY, position.width - buttonPaddingRight, buttonHeigth), (knowledgeName)) ){
				if(EditorApplication.isPlaying){
					knowledgeManager.GetKnowledge (playerKnowledge);
				}
			}
			row01PositionY += buttonPadding;
		}
		else {
			EditorGUI.LabelField(Rect(entryLeftPadding,row01PositionY,position.width,buttonHeigth), knowledgeName);
			row01PositionY += buttonPadding;
		}
	}

What I really want to figure out is the variable knowledgeName! In the current example where I do a ToString() I just end up getting the button/label called ActorKnowledge.

Any help would be amazing!

UPDATE:

SO I think I phrased this incorrectly.
What I meant is, I want the name of the variable that was created using this class, so for example I have these:

		knowsAboutPocketWatch = new ActorKnowledge(false, playerKnowledgeList);
		knowsAboutJournal = new ActorKnowledge(false, playerKnowledgeList);
		canProveSarahInnocence = new ActorKnowledge(false, playerKnowledgeList);

and I would like them to show in the editor with their names rather than as “ActorKnowledge”

one simple solution is using

this.GetType().Name;

objectName.GetType().Name;

But remember that it wont work if it is a static class.

I’m not sure if JavaScript has typeof, but have you tried typeof(ClassInQuestion).ToString()