To String with 'n' zeros in front

T$$anonymous$$s is a simple programming problem.

There's tons of ways you could do it with. But to do it from your float number instance, you need to make a float extension. Watch t$$anonymous$$s to understand how to make extensions.

 public static class FloatExtensions
 {
     public static string PrependWithNum(t$$anonymous$$s float f, int numToInsert, int nTimes)
     {
         string str = f.ToString();
         for (int i = 0; i < nTimes - 1; i++) {
             str = str.Insert(0, numToInsert.ToString());
         }
         return str;
     }
 }

Now you could do stuff like:

 float f = 123.456f;
 string zeroes = f.PrependWithNum(0, 4); // the first parameter is what you want to prepend (in t$$anonymous$$s case, 0)
 string ones   = f.PrependWithNum(1, 6); // the second one is how many digits will be before the decimal point, after the prepending including what you prepended (in t$$anonymous$$s case, 6)
 print (zeroes); // 0123.456
 print (ones);   // 111123.456;

A brief explanation about extensions:

• Extensions allow you to extend existing classes. Extend means adding methods to the class that you're extending.

• Your extension class must be static, a good conversion is to name the class with what you're extending

• the word Extensions, like StringExtensions, FloatExtensions, etc.

    public static class FloatExtensions
  
  

• Your extension methods also must be marked static.

    public static string PrependWithNum
  
  

• If you're confused about the t$$anonymous$$s float f parameter I passed, t$$anonymous$$s is the actual instance that called the method, for ex:

    float myFloat = 123.123f;
      print (myFloat.PrependWithNum(5, 0); // 00123.123;
  
     
  

  The first parameter that gets passed into PrependWithNum is actually myFloat

If you didn't like extensions, just write a normal static helper method and throw it somewhere:

 public static string PrependWithNum(float f, int numToInsert, int nTimes)
 {
     string str = f.ToString();
     for (int i = 0; i < nTimes - 1; i++) {
         str = str.Insert(0, numToInsert.ToString());
     }
     return str;
 }

But then you'd have to call it like:

 float f = 34.34f;
 print (whereverYouPutYourMethodIn.PrependWithNum(f, 0, 3)); // 034.34

Hope that was informative and helpful :)