Display label for different screensize

Question

I need to display label for different screen sizes on android. I used below code. When i running on device label displaying 2 times. Is if condition not working?

 if(Screen.height >= 1280){
             
 GUI.skin.label = style_1;
             GUI.skin.label.padding.top=200;
             
         GUILayout.Label("1. Print the alphabet image targets located at", style_1);
 }
 
 if(Screen.height >= 800){
         
         GUI.skin.label = style;
             GUI.skin.label.padding.top=100;
             
         GUILayout.Label("1. Print the alphabet image targets located at", style);
 }

Answer 1

Answer by zharik86 · Jan 16, 2014 at 08:13 AM

In your case it is necessary to use GUI.matrix:

  void OnGUI() {
   //write your GUI elements for one screen resolution, for example, 1280x720
   float scalex = (float)(Screen.width) / 1280.0f;
   float scaley = (float)(Screen.height) / 720.0f
   GUI.matrix = Matrix4x4.TRS(new Vector3(0, 0, 0), Quaternion.identity, new Vector3(scalex, scaley, 1);
   //and, for example, I create label with text
   GUI.Label(new Rect(0, 200, 600, 100), "1. Print the alphabet image targets located at");
  }

I hope it to you will help.

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magu7 · Feb 16, 2017 at 07:11 PM 0

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thanks bro, this helped me a lot to scale all my gui windows labels and buttons easier

RobAnthem magu7 · Feb 16, 2017 at 07:39 PM 0

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Why would you even use the old GUI? The new UI can auto-scale, or stretch to fit.

Display label for different screensize

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