what is wallJumpContactNormal.y ?

Question

I know that the normal indicates where an object surface is facing,

 if(Mathf.Abs(wallJumpContactNormal.y) < 0.2f)
     
         wallJumpContactNormal.y = 0;
 ///=====================================================================
  Help me if Im getting this above part wrong... I read it as...
  Ignore the height of the normal which is 20% above or below
 //======================================================================



 if(Mathf.Abs(wallJumpContactNormal.y) < 0.2f)
     {
         wallJumpContactNormal.y = 0;
         moveDirection = wallJumpContactNormal.normalized;
         //Wall jump gives at least trotspeed
         moveSpeed = Mathf.Clamp(moveSpeed * 1.5f, trotSpeed, runSpeed);
     }
     else
     {
         moveSpeed = 0;
     }

Answer 1

Answer by robertbu · Aug 10, 2014 at 01:53 PM

I would read this as: if the surface hit is modestly tilted up, or an any way tilted down, treat the surface as if it was straight up and down (not tilted).

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Answer 2

Answer by Elson · Aug 12, 2014 at 07:58 PM

I got your point:

That way, straight up would be 0 and up to 20% tiltness(inclination) unity'd consider as straight up anyways and the player'd receive a force to jump out of the wall 105%, not less then trotSpedd and no more than runSpeed. Otherwise if the inclination is greater or less then this value(20%) it wouldn't receive no speed at all.

Is that what you mean?

At first I thought that the heith of the wall was the thing that'd trigger the player speed and direction setting. It'd only be active beyond 20% but that in fact would be inefficient if we'd jump from one wall to another cuz its height'd go over this amount.

I have just one more question...

''wallJumpContactNormal.y'' is comparing y(height) value to another value...(if it goes over/below 20%) if straight Up is zero... is positive 1 at -x?

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what is wallJumpContactNormal.y ?

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