checking if 2 out of 4 is true no matter which one

Question

Let's say that I have a switch statement like so

     switch(id){
     case 1:
         break;
     case 2:
         break;
     case 3:
         break;
     case 4:
         break;
     }

How can I detect in an easy manner without overloading my script with tons of code wether 2 out of these 4 are true, may it be 1 and 2 or 2 and 3 or 4 and 1, whenever 2 are true I need something to happen how can I achieve very easily and cleanly? (I know how to do it but I want a nice and clean way if possible)

Thanks!

Answer 1

Answer by Kiwasi · Aug 27, 2014 at 10:59 AM

Pseudo code

 private bool[] bools = new bool[4];
 private int count = 0;
 
 foreach(bool myBool in bools){
     if(myBool){
         count++;
     }
 }
 if (count>=2){
     return true;
 } else {
     return false;
 }

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Paulo-Henrique025 · Aug 27, 2014 at 05:48 PM 1

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You can also add them to a list if you want to use named vars instead of an array :)

Kiwasi · Aug 27, 2014 at 07:55 PM 0

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That's true. Foreach will run on any collection type.

Answer 2

Answer by Ellandar · Aug 27, 2014 at 11:09 AM

Hi Jan,

I think the problem here is you want something that switch cannot provide. Basically switch is shorthand for an if-elseif block of code, thus your id variable can only be equal to a single case at any run through.

Without much more info, I can only give you a possible solution that may work.

 int trueCounter;
 
 if(id == case1)  trueCounter++;
 if(id == case2)  trueCounter++;
 if(id == case3)  trueCounter++;
 if(id == case4)  trueCounter++;
 
 if(trueCounter == 2)
 {
    // your stuff happens here
 }

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checking if 2 out of 4 is true no matter which one

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