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This question was closed Sep 29, 2014 at 09:39 AM by Graham-Dunnett for the following reason:

Duplicate Question

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Question by Dext · Sep 27, 2014 at 12:40 PM · nullreferenceexception

NullReferenceException: Object reference not set to an instance of an object

I have this particle script, but when I try to activate the RPV void I get this error message

NullReferenceException: Object reference not set to an instance of an object particletrigger.Update () (at Assets/Photon Unity Networking/Resources/NetworkScript/particletrigger.cs:22)

 using UnityEngine;
 using System.Collections;
 
 public class particletrigger : MonoBehaviour {
 
 
     private PhotonView myPhotonView;
     // Use this for initialization
     void Start () {
 
         myPhotonView = GetComponent<PhotonView>();
  
     }
     
     // Update is called once per frame
     public void Update () {
 
         if(Input.GetKeyDown(KeyCode.Space))
             networkView.RPC("DoExploder",RPCMode.All, new object[]{15});
 
         else if (Input.GetKeyDown(KeyCode.Return)){
             this.myPhotonView.RPC("DoExploder", PhotonTargets.All, new object[]{122});
 
         }
     
     
     }
 
     [RPC]
     public void DoExploder(int count){
 
         Debug.Log("Check");
         particleSystem.Emit(count);
 
     }
 }
 

 
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avatar image smoggach · Sep 29, 2014 at 03:52 AM 0
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Where is networkView declared? Are you absolutely positive there is a PhotonView attached to the object?

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Answer by Pendrokar · Sep 29, 2014 at 08:42 AM

NullReferenceException: Object reference not set to an instance of an object particletrigger.Update () (at Assets/Photon Unity Networking/Resources/NetworkScript/particletrigger.cs:22)

This is the line:

this.myPhotonView.RPC("DoExploder", PhotonTargets.All, new object[]{122});

"this" is definitely set, so "myPhotonView" must be the one that is "null" and you are trying to a function on it, meaning that the following failed to find the component:

myPhotonView = GetComponent();

The PhotonView must be attached to the GameObject that this script is running in for that line to work.

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