Create an array of classes, of different type.

Question

I have this class:

 public static class CharTypes {
     public class Foo {
         function action1 () {
             
         }
         
         function action2 () {
             
         }
     }
     public class Bar {
         function action1 () {
             
         }
         
         function action2 () {
             
         }
     }
     var index = [
         Foo,
         Bar
     ];
 }

And the internal system stores those types by number, so to access a specific action from a type, I would do this:

 CharTypes.index[internalStuff.id].action1();

But this throws

BCE0019: 'action1' is not a member of 'System.Type'.

How do I make the index a type that allows me to reference actionX()?

Answer 1

Best Answer

Answer by dvidunis · Nov 26, 2014 at 04:05 PM

Nevermind, figured it out. I made a CharTypeTemplate class, and made all others extend it.

 public static class CharTypes {
     private class CharTypeTemplate {
     function action1 () {}
     function action2 () {}
 }
      public class Foo extends CharTypeTemplate {
          function action1 () {
              
          }
          
          function action2 () {
              
          }
      }
      public class Bar extends CharTypeTemplate {
          function action1 () {
              
          }
          
          function action2 () {
              
          }
      }
      var index:CharTypeTemplate = [
          Foo,
          Bar
      ];
  }

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Create an array of classes, of different type.

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